shell bypass 403

UnknownSec Shell

: /lib/.build-id/04/ [ drwxr-xr-x ]

name : fdc0f304841e3ab09f539c6a4de7a020777f65
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Infinite iterators:
count([n]) --> n, n+1, n+2, ...
cycle(p) --> p0, p1, ... plast, p0, p1, ...
repeat(elem [,n]) --> elem, elem, elem, ... endlessly or up to n times

Iterators terminating on the shortest input sequence:
chain(p, q, ...) --> p0, p1, ... plast, q0, q1, ... 
compress(data, selectors) --> (d[0] if s[0]), (d[1] if s[1]), ...
dropwhile(pred, seq) --> seq[n], seq[n+1], starting when pred fails
groupby(iterable[, keyfunc]) --> sub-iterators grouped by value of keyfunc(v)
ifilter(pred, seq) --> elements of seq where pred(elem) is True
ifilterfalse(pred, seq) --> elements of seq where pred(elem) is False
islice(seq, [start,] stop [, step]) --> elements from
       seq[start:stop:step]
imap(fun, p, q, ...) --> fun(p0, q0), fun(p1, q1), ...
starmap(fun, seq) --> fun(*seq[0]), fun(*seq[1]), ...
tee(it, n=2) --> (it1, it2 , ... itn) splits one iterator into n
takewhile(pred, seq) --> seq[0], seq[1], until pred fails
izip(p, q, ...) --> (p[0], q[0]), (p[1], q[1]), ... 
izip_longest(p, q, ...) --> (p[0], q[0]), (p[1], q[1]), ... 

Combinatoric generators:
product(p, q, ... [repeat=1]) --> cartesian product
permutations(p[, r])
combinations(p, r)
combinations_with_replacement(p, r)
izip_longest(iter1 [,iter2 [...]], [fillvalue=None]) --> izip_longest object

Return an izip_longest object whose .next() method returns a tuple where
the i-th element comes from the i-th iterable argument.  The .next()
method continues until the longest iterable in the argument sequence
is exhausted and then it raises StopIteration.  When the shorter iterables
are exhausted, the fillvalue is substituted in their place.  The fillvalue
defaults to None or can be specified by a keyword argument.
repeat(object [,times]) -> create an iterator which returns the object
for the specified number of times.  If not specified, returns the object
endlessly.Private method returning an estimate of len(list(it)).izip(iter1 [,iter2 [...]]) --> izip object

Return a izip object whose .next() method returns a tuple where
the i-th element comes from the i-th iterable argument.  The .next()
method continues until the shortest iterable in the argument sequence
is exhausted and then it raises StopIteration.  Works like the zip()
function but consumes less memory by returning an iterator instead of
a list.count(start=0, step=1) --> count object

Return a count object whose .next() method returns consecutive values.
Equivalent to:

    def count(firstval=0, step=1):
        x = firstval
        while 1:
            yield x
            x += step
Return state information for pickling.ifilterfalse(function or None, sequence) --> ifilterfalse object

Return those items of sequence for which function(item) is false.
If function is None, return the items that are false.ifilter(function or None, sequence) --> ifilter object

Return those items of sequence for which function(item) is true.
If function is None, return the items that are true.compress(data, selectors) --> iterator over selected data

Return data elements corresponding to true selector elements.
Forms a shorter iterator from selected data elements using the
selectors to choose the data elements.permutations(iterable[, r]) --> permutations object

Return successive r-length permutations of elements in the iterable.

permutations(range(3), 2) --> (0,1), (0,2), (1,0), (1,2), (2,0), (2,1)combinations_with_replacement(iterable, r) --> combinations_with_replacement object

Return successive r-length combinations of elements in the iterable
allowing individual elements to have successive repeats.
combinations_with_replacement('ABC', 2) --> AA AB AC BB BC CCcombinations(iterable, r) --> combinations object

Return successive r-length combinations of elements in the iterable.

combinations(range(4), 3) --> (0,1,2), (0,1,3), (0,2,3), (1,2,3)product(*iterables) --> product object

Cartesian product of input iterables.  Equivalent to nested for-loops.

For example, product(A, B) returns the same as:  ((x,y) for x in A for y in B).
The leftmost iterators are in the outermost for-loop, so the output tuples
cycle in a manner similar to an odometer (with the rightmost element changing
on every iteration).

To compute the product of an iterable with itself, specify the number
of repetitions with the optional repeat keyword argument. For example,
product(A, repeat=4) means the same as product(A, A, A, A).

product('ab', range(3)) --> ('a',0) ('a',1) ('a',2) ('b',0) ('b',1) ('b',2)
product((0,1), (0,1), (0,1)) --> (0,0,0) (0,0,1) (0,1,0) (0,1,1) (1,0,0) ...chain.from_iterable(iterable) --> chain object

Alternate chain() constructor taking a single iterable argument
that evaluates lazily.chain(*iterables) --> chain object

Return a chain object whose .next() method returns elements from the
first iterable until it is exhausted, then elements from the next
iterable, until all of the iterables are exhausted.imap(func, *iterables) --> imap object

Make an iterator that computes the function using arguments from
each of the iterables.  Like map() except that it returns
an iterator instead of a list and that it stops when the shortest
iterable is exhausted instead of filling in None for shorter
iterables.starmap(function, sequence) --> starmap object

Return an iterator whose values are returned from the function evaluated
with an argument tuple taken from the given sequence.islice(iterable, [start,] stop [, step]) --> islice object

Return an iterator whose next() method returns selected values from an
iterable.  If start is specified, will skip all preceding elements;
otherwise, start defaults to zero.  Step defaults to one.  If
specified as another value, step determines how many values are 
skipped between successive calls.  Works like a slice() on a list
but returns an iterator.takewhile(predicate, iterable) --> takewhile object

Return successive entries from an iterable as long as the 
predicate evaluates to true for each entry.dropwhile(predicate, iterable) --> dropwhile object

Drop items from the iterable while predicate(item) is true.
Afterwards, return every element until the iterable is exhausted.cycle(iterable) --> cycle object

Return elements from the iterable until it is exhausted.
Then repeat the sequence indefinitely.tee(iterable, n=2) --> tuple of n independent iterators.Iterator wrapped to make it copyableReturns an independent iterator.Data container common to multiple tee objects.groupby(iterable[, keyfunc]) -> create an iterator which returns
(key, sub-iterator) grouped by each value of key(value).
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